Miscelleneous

C L DUBEY – EXERCISE – 02 : Simpson’s Rule

Ordinate
SM
Product
Lever
Moment
14.4 1 14.4 12h 172.8h
12.0 3 36.0 15h 540h
9.3 3 27.9 18h 502.2h
6.0 1 6.0 21h 126h
    SOP=84.3   SOM = 1341h

Moment = (3 ⨯ 3/8) ⨯ 1341
= 1508.625

Area = 9/8 ⨯ 84.3
= 94.83

Total moment = 2685.825
Area = 299.43

Therefore,
Geometric Centre = ( Total moment / Area)

= 8.97m from top.
Q9. A ship’s water plane is 216m in length. The half ordinates of the waterplane commencing from forward are as follows;
0.4, 4.4, 8.8, 11.0, 11.6, 11.8, 11.8, 11.6, 9.6, 7.0, 0.4 respectively.
The spacing between the first three and last three ordinates is half of the spacing between the other half ordinates. Calculate her waterplane area and the position of the CF with respect to the midlength.
Solution –
Ordinate
SM
Product
Hours  
Moment
0.4 0.5 0.2 0h 0h
4.4 2 8.8 0.5h 4.4h
8.8 1.5 13.2 h 13.2h
11.0 4 44.0 3h 8.8h
11.6 2 23.2 3h 69.6h
11.8 24 47.2 4h 181.8h
11.8 1.5 23.6 5h 118h
11.6 4 46.4 6h 278h
9.6 1.5 14.4 7h 100.8h
7.0 2 14.0 7.5h 105h
0.4 0.5 0.2 8h 1.6h
  SOP=235.2   SOM=967.8h

SSR 06

Area = 2 ⨯ 27/3 ⨯235.2
= 4233.6m2

COG from one end = 111.099

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Graduated from M.E.R.I. (Mumbai). A cool, calm, composed and the brain behind the development of the database. The strong will to contribute in maritime education and to present it in completely different and innovative way is his source of inspiration.

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