X = 3.253m
Q2. The breadths of a ship’s water-plane 120m long, measured at equal intervals from aft, are: 1.2, 9.6, 13.2, 15.0, 15.3, 15.6, 15.6, 14.7, 12.9, 9.0 and 0.0m respectively. Find:
-
The water plane area;
-
TPC in sea water;
-
FWA if displacement is 6690t.
Solution –
Ordinate |
SM |
Product |
|
| 1.2 | 1 | 1.2 | |
| 9.6 | 4 | 38.4 | |
| 13.2 | 2 | 26.4 | |
| 15.0 | 4 | 60.0 | |
| 15.3 | 2 | 30.6 | |
| 15.6 | 4 | 62.4 | |
| 15.6 | 2 | 31.2 | |
| 14.7 | 4 | 58.8 | |
| 12.9 | 2 | 25.8 | |
| 9.0 | 4 | 36.0 | |
| 0.0 | 1 | 0.0 | |
| 370.8 | |||

Water plane Area = ( H x SOP )/ 3
= 1483.2m2
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