X = 3.253m
Q2. The breadths of a ship’s water-plane 120m long, measured at equal intervals from aft, are: 1.2, 9.6, 13.2, 15.0, 15.3, 15.6, 15.6, 14.7, 12.9, 9.0 and 0.0m respectively. Find:
-
The water plane area;
-
TPC in sea water;
-
FWA if displacement is 6690t.
Solution –
Ordinate |
SM |
Product |
|
1.2 | 1 | 1.2 | |
9.6 | 4 | 38.4 | |
13.2 | 2 | 26.4 | |
15.0 | 4 | 60.0 | |
15.3 | 2 | 30.6 | |
15.6 | 4 | 62.4 | |
15.6 | 2 | 31.2 | |
14.7 | 4 | 58.8 | |
12.9 | 2 | 25.8 | |
9.0 | 4 | 36.0 | |
0.0 | 1 | 0.0 | |
370.8 |
Water plane Area = ( H x SOP )/ 3
= 1483.2m2
Give me your email id, i will send the answer to question no. 5 and 6 of exercise 2 (simpson’s rule) so that u may upload and update the article…
[email protected]