Miscelleneous

C L DUBEY – EXERCISE – 09 (GROUNDING)

  • Trim caused = 450 ⨯ 48/110 ⨯ 100 = 1.964m

Ta = 1.014,
Tf =   ( Tc – Ta)
= 0.95m

Rise = 450/1600 
        = 0.281m

  Fwd Aft
Draft 4.200m 5.100m
-0.281m -0.281m
3.919m 4.819m
-0.950m +1.014m
2.969m 5.833m
Q4. A vessel of length 120m, Displacement 6400 tonnes, TPC 15 tonnes, MCTC 110tm, Km 6.4m, KG 5.1m, CF 2m for’ d of the midlength grounds on a rock 45m for’d of midlength the tide then by 80 cm.  Calculate the residual GM then.
Solution –

We can calculate fall in tide –

Fall in tide = P/ TPC + ( P x AL / MCTC) + AL/ LBP  
80 =    P/15 + P ⨯ 43/110 ⨯ 43/120
So, P = 386.95 cm.
GG1 = 386.95 ⨯ 6.4/ 6400
= 0.3869m

Residual GM = 0.91m

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Manish Mayank

Graduated from M.E.R.I. (Mumbai). A cool, calm, composed and the brain behind the development of the database. The strong will to contribute in maritime education and to present it in completely different and innovative way is his source of inspiration.

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