Miscelleneous

C L DUBEY – EXERCISE – 08 (DRY DOCKING)

Fluid GM = 1.047m
New GM = (1.047 – 0.382)m
                 = 0.665m
  1. A vessel of length 140m, displacement 5210t, KG 5.8m, KM 6.1m, MCTC 130tm, TPC 14t, CF 2m abaft midlength is afloat in a drydock at a draft of forward 3.9m and Aft 5.2m. the water level in the dock is 6m above the top of the blocks. Calculate the virtual GM and drafts F & A, when the water level is lowered by 1.5m.
Solution –

Draft Fwd = 3.9 m,
Draft aft = 5.2m
Corn to aft draft = 0.631m
Hydrostatic draft = 4.568m
Now, Water  level = 4.5m.

Since water level is almost same to hydrostatic draft we will consider that ship has taken block aft but not overall.

Reduction in aft draft = 70cm
Or, 70 = P/14 + P ⨯ 68/130 ⨯ 68/140

Or, P = 215.06 tonnes
GG1 = P ⨯ KM/W
= 215.06 ⨯6.1/5210
= 0.252m

GM = (0.3 – 0.252)m
       = 0.048m

Now Trim caused = 215.06 ⨯ 68/130 ⨯ 100
= 1.125m,
Ta = 1.125 ⨯ 68/140
= 0.546m, Tf = 0.578m

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Graduated from M.E.R.I. (Mumbai). A cool, calm, composed and the brain behind the development of the database. The strong will to contribute in maritime education and to present it in completely different and innovative way is his source of inspiration.

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