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A ship displacing 4000t has GM 1.0m (KM 10.0 m and KG 9.0 m) and is listed 10 degree to port .If 16000t of cargo is now loaded on the centre line and the final GM is 1.0m KM 9.0m and KG 8.0m state weather the list would change .if yes , find the new list .
Solution :
Displacement (W) = 4000t,
GM = 1.0m (initial) ,
list = 10 degree (P)
W = 16000t, G
M = 1.0m (final)
We know that:
Listing moment (LM) = (W x GM tanθ)
= (4000 x 1 x tan 100)
= 705.3 tm
According to question , 16000 t of cargo loaded
So Final W = (16000 + 4000)
= 20,000t
But, Initial GM = Final GM
Initial LM = Final LM
Again we know that :
Tanθ = (FLM/(W x GM )
= 705.3/(20000 x 1)
= 2 degree 1 minute ( P).
Hence we can say that,(Yes) list would change due to the loading of cargo.
Question no.19. Sub question 3
Kg will change when being shifted from derrick to lower hold 2m above kg so GM will also change
Gm= 0.58 and list will be 1.60degree to starboard
Q.7
Final listing moment is 700(p), not starboard
For case 2; since, both the tanks are slack, therefore, Total FSC = 0.3456m x 2 = 0.6912m.
Good luck
Ex -11 List Ques No. 18, Part 2 have a mistake in total Vertical movements…..it should be 87000 not 87200 which gives us a final answer as follows
List = 3* 51′ or 3.85 degrees
Q.7 listing moment is 700 port not stbd