EXERCISE 34 – AZIMUTH STAR (Numerical Solution)

GMT  01 Dec 07h 39m 22s

GHA Ȣ(01d 07h)             175˚  30.7’                                           Dec *        N  38˚  47.6’
Incr. (39m 22s)            009˚  52.1’7                                             Lat            48˚  57’ N
GHA  Ȣ                            185˚  22.8’
Long (W)                   (-) 173˚  18.0’
LHA  Ȣ                             012   04.8’
SHA  *                      (+)080˚  41.7’
LHA  *                           092˚  46.5’

P  = LHA
= 92˚  46.5’

We know that :

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Azimuth = N 60.53˚W

T Az          = 299.47˚ (T)
C Az          = 296.00˚ (C)
Error         = 3.5˚ E
Variation  = 1.0˚ E
Deviation = 2.5˚E

  1. On 01ST May 2008, AM at ship in DR 62˚ 11’S 179˚ 58’ E, the azimuth of the star SPICA was 312˚(C) when the GPS clock showed 13h 00m 08s. If variation was 10˚E, calculate the deviation of the ship’s head.

                                d     h     m     s
GMT                       30   13    00  08
LIT (E)                            11   59   52
LMT                        01   01  00   00

GMT                      30d 13h 00m 08s

GHA Ȣ(30d 13h)       053˚  50.6’                                           Dec *         S  11˚  12.5’
Incr. (00m 08s)        000˚  02.0’
GHA Ȣ                       053˚  52.6’
SHA  *(+)                  158˚  35.1’
GHA *                       212˚  27.7’
Long (E)             (+)  179˚  58.0’
LHA  *                      032˚  25.7’

P = LHA
= 032˚  25.7’

About the author

Vikrant_sharma

3 Comments

  • The direction of azimuth .. don’t you think should be N34.4W. it’s written east..in question no. 5 of azimuth star. Please let me know if it’s correct.

  • Good day Sir,

    Just a short question, how do we name every deviation obtained from Azimuth Sun sailing? How do we know its east or west? Thank you

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