Therefore, condition 1 satisfied
| Heel | Ordinate | SM | Product |
| 0 | 0.0 | 1 | 0 |
| 10 | 0.15 | 4 | 0.60 |
| 20 | 0.33 | 2 | 0.66 |
| 30 | 0.645 | 4 | 2.28 |
| 40 | 0.610 | 1 | 0.610 |
| 4.45 |
Area = 10/3 ⨯ 4.45/57.3
= 0.259m radian
Area of triangle = 0.5 ⨯ 12 ⨯ 0.19/57.3
= 0.0199m radian
Area of trapezium = 0.5 ⨯ (0.19 + 0.16) ⨯ 28/57.3
= 0.085 m radian
Residual area = 0.16m radian ˃ 0.075
Therefore, condition 3 satisfied.
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