Q7. The water plane areas of a ship at 1m intervals, commencing from the keel are as follows:
Draft (m) |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
Areas (sq.m) |
5850 |
5885 |
5900 |
5915 |
5943 |
5975 |
5995 |
Calculate her KB and FWA at a draft of 6m.
Solution –
Draft |
Area |
SM |
Product |
Lever |
Product of moment |
0 | 5850 | 1 | 5850 | 0h | 0h |
1 | 5885 | 4 | 23540 | 1h | 23540h |
2 | 5900 | 2 | 11800 | 2h | 23600h |
3 | 5915 | 4 | 23660 | 3h | 70980h |
4 | 5943 | 2 | 11886 | 4h | 47544h |
5 | 5975 | 4 | 23900 | 5h | 119500h |
6 | 5995 | 1 | 5995 | 6h | 35970h |
SOP = 106631 | SOM = 321134h |
KB = 3.012m
Volume = 3554.667
W = 36432.258
TPC = A/100 ⨯ density of water
= 61.448
We can calculate – FWA = W/40 ⨯ TPC
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