Miscelleneous

C L DUBEY – EXERCISE – 08 (DRY DOCKING)

  • When water level is further lowered by 1.0m

Level = 4.5m
Since water level < hydrostatic draft ship has taken over block over all.
Reduction in Hydrostatic draft = (5.063 – 4.5)m
                                                                 = 0.563m

Or, 56.3 = P/15
Or, P = 844.5 tonnes

GG1 = P ⨯ KM/W
= 0.870m

Old GM = 0.6m
Therefore, New GM = (old GM – GG1 )
                                         = -0.270m
  1. A vessel of L = 145m, CF = 3 mts forder of *, MCTC = 150 mt TPC = 18 t, KM = 7.5m, KG = 6.9, w = 11200 at a draft of F = 3.72m, A = 5.70m is floating in a drydock where depth of water is 6.5m above the top of the blocks. Calculate the vessel’s residual GM and her draft’s F & A, when the W/T is lowered by 1.5m.
Solution –

When level is lowered by 1.5m then water level = 5.0m
Correction to aft draft =( trim ⨯ LCF)/ LBP
= 1.031m
Hydrostatic draft = 4.669m

Since water level is greater than 4.669m it means stern has taken to block while forward end is still afloat.

Reduction in aft draft = 70cm
Or, 70 = P/18 + P ⨯ 75.5/150 ⨯ 75.5/145
Or, P = 220.4 tonnes

GG1 = P ⨯ KM/W
   = 0.147m

Virtual GM = (0.6 – 0.147)m
= 0.147m

Trim caused = Tc = 220.4 ⨯ 75.5/150
= 110.93
Or = 1.109m

Rise = 220.4/18 ⨯ 100
= 0.122m

Ta = 1.109 ⨯ 75.5/145
= 0.577m

About the author

Manish Mayank

Graduated from M.E.R.I. (Mumbai). A cool, calm, composed and the brain behind the development of the database. The strong will to contribute in maritime education and to present it in completely different and innovative way is his source of inspiration.

Leave a Comment