8. A box –shaped of 2000t displacement is 50m x 10m x 7m. Calculate her RB% in FW
Solution :
Given :- W = 2000t,
(L x B x H) of box shaped vessel = (50m x 10m x 7m)
Total volume = 3500m3
W = ( u/w volume) x (density)
2000 = (u/w volume) x (1.00)
u/w volume = 2000 m3
Above water volume = (Total volume) – (u/w volume )
= (3500 – 2000)
= 1500 m3
RB % = (Above water volume) / (total volume ) x 100
RB % = (1500 /3500)x 100
= 42.857%
9. The TPC of a ship in SW is 30. Calculate her TPC in FW and in DW of RD1.018.
Solution:
We know that:-
TPC = (A / 100) x (density)
30 = (A / 100) x (1.025)
A = (30 x 100)/ 1.025
A = 2926.83 m2
TPC in FW can be determined as = ( 2926.83/ 100)x(1)
=29.268 t/cm.
TPC in DW can be determined as = (2926.83 / 100) x(1.018)
= 29.79 t/cm.
many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…anyways thanks for this website
many questions have wrong answers in various exercises,,at least book ke end me answers ko chk kar lete…
what is the draft of a box shape steel (L=4 meters , B= 4 meters , Depth = 0.60 meters)
floating in a salt water density 1.028 and the total weight of the steel box with steel on top of it is 1500 kg
question 5 is wrong. you forget to take the u/w vol and multiply by the sw density.
sir exercise no 4 problem no 7 draft you had taken is wrong it is not 4.1 it is 6.1 mtr