Miscelleneous

C L DUBEY – EXERCISE – 08 (DRY DOCKING)

Therefore, New Virtual GM = (0.7 – 1.280)m
                                                       = -0.580m
  1. A vessel is to be dry docked in a damaged condition. She is floating at F 12.60m and A 9.00m. it is estimated that she will take the blocks 15m aft of the forward perpendicular. Estimated data: KG 8.9m, KM 9.4m, TPC 21.3 t/cm, MCTC 290 tm/cm, AF 76m, LBP 165m displacement 19500 tonnes.
  • Is it safe to dry dock the vessel in this condition? Support your answer with calculation.
  • Estimate the drafts at the perpendiculars on taking to the blocks fore and aft.
Solution –
  • Trim = 3.60m, d = 74m

P = (trim ⨯ MCTC)/d
= (360 ⨯ 290)/74
= 1410.8 tonnes

GG1 = (P ⨯ KM)/W
= (1410.8 ⨯ 9.4)/19500
= 0.680m

Old GM = 0.5m,
GG1 = 0.680m

About the author

Manish Mayank

Graduated from M.E.R.I. (Mumbai). A cool, calm, composed and the brain behind the development of the database. The strong will to contribute in maritime education and to present it in completely different and innovative way is his source of inspiration.

Leave a Comment