Stability -I : Chapter 1

  1. A rectangular tank measures 16mx15mx6m. How many tonnes of oil of RD 0.78 can it hold?
SOLUTION:

Given : L =16m , B = 15m, H = 6m, RD=0.78qes 1

Volume of rectangle =(LxBxH)
=16x15x6
=1440m3

We know that :
Density = Mass /Volume
0.78 =Mass/1440m3

Hence, Mass =1123.2 tonnes

 

  1. A cylindrical tank of diameter 8m is 10m high.400t of oil of RD 0.9 is poured in to it. Find the ullage, assuming π to be 3.1416.
SOLUTION:

Given: Diameter = 8m,

Radius = (d/2)m
=(8/2)m
=4m
Height =10m
Mass = 400t
RD =0.9qes 2

We know that:
Volume of the cylindrical tank = π2h
= 3.1416 x 4 x 4 x 10
=502.656m3

We know that:
Density = (Mass/Volume)
0.9 = 400/ (Volume of the oil)

Hence, Volume of the oil = 400/0.9
=444.44m3

Depth of oil = volume/area
Area of cylinder   =( π2r)
 =(3.1416 x 4 x 4)
 =502656m3

We can calculate Depth of oil = (volume of oil)/ ( area of cylinder)
 = (444. 44)/(50.2656 )
=8.8418 m

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Amit Sharma

Graduated from M.E.R.I. Mumbai (Mumbai University), After a brief sailing founded this website with the idea to bring the maritime education online which must be free and available for all at all times and to find basic solutions that are of extreme importance to a seafarer by our innovative ideas.

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