What is effect of wind on Ship Manoeuvring or Motion ?

The wind-force can be calculated with the   formula:

wind-force = 0.004 x W x  v

 where: W = windage in square feet

             v = wind speed in knots wind-force is expressed in pounds

Wind speed as well as wind direction, ship’s speed, and ship’s heading are not at all times constant during the maneuver. A slight error in wind speed is of much greater consequence than a similar error in assumed windage of the tanker. The following approximations for assumed windage will therefore be good enough for our purpose.

W (abeam) = LOA x D – LBP x mean draft
W (on the bow ) = В x D – В x draft forward

where: LOA = length overall

           LBP = length between perpendiculars

          В = breadth, molded

         D = depth, molded

For intermediate angles we take the median between the direct proportional value and the value proportional to the sine of the angle of incidence.ship

On the following pages we will examine the effect of a 25-knot wind on a 70,000-dwt tanker in ballast; draft 16 feet forward and 26 feet aft; LOA = 800 feet; LBP = 765 feet; В = 115 feet; D = 56 ft; engine power = 20,000 HP; and stern power = 16,000 HP.

Head Wind

A wind-force of 25 knots exerts a longitudi­nal force of about 6 tons on a tanker of 70,000 dwt in ballast. A long as the ship is heading right into the wind, there is no transverse component of the wind-force. When the ship is moving ahead through the water, we have good steering control with the pivot point forward.

Under sternway, the ship is in ail unsta­ble equilibrium with the pivot point aft. If a transverse wind-force develops, a long distance to the pivot point and consequently much leverage is created. Since the rudder has very little effect under sternway,

we depend on a forward tug or on a bow thruster to keep the ship under control.

Wind on the Bow

With the wind on the bow, there will be an  increasing transverse wind-force when the bow falls off. The transverse wind-force grows to about 15 tons when the 25-knot wind is 30 degrees on the port bow and in­creases to about 27 tons when the ship is heading 60 degrees off the wind. The longi­tudinal wind-force decreases to about 4 tons with the wind 30 degrees on the bow and to about 2 tons with the wind 60 de­grees on the bow.ship 1

When moving ahead through the water, the ship will have a tendency to swing to port. Under sternway, there will be a strong tendency for the bow to fall off to starboard; it is only by coming ahead on   • the engine and bringing the pivot point forward that we can check the swing.

Beam Wind

On the beam, the transverse wind-force  of 25 knots exerts a force of 36 tons. The point of impact is forward of the midship because of the trim. Whether or not the tugs can keep the ship under control de­pends on the horsepower of the tugs and the side on which they are made fast.ship 2

Suppose that the ship is assisted by two tugs of 2,000 HP each, one tug forward, one aft. The bollard pull of the tugs is about 35 tons, but in backing they pull only about 13 tons. When the tugs are made fast on the starboard side, the combined force of the tugs can move the ship up against the wind. Backing on the port side, the tugs cannot hold the ship.

With the tugs on the port side, we need at least a strong tug forward. A tug of 4,000 HP, for instance, having   bollard

 pull of 65 tone and 29 tons on backing, could, in combination with the 2,000 HP tug aft, hold the ship, provided we prevent exces­sive dynamic loads on the tug’s headlines.

When the assisted ship is dead in the water and we have balanced the forces of wind and tugs, we have created a more or less static situation where the forward tug takes more of the load than the after tug.ship 3

Under forward motion (fig. 22), we have the rudder with sufficient leverage to cor­rect any imbalance in forces. Let us assume that the point of impact of the wind-force is 40 feet forward of the midship and that the forward tug is made fast forward on the main deck, 150 feet from the stem; the after tug, aft on the main deck, 200 feet from the stern. Let us further assume that the pivot point under forward motion is about 200 feet from the stem, providing the rudder with a lever of 600 feet. As long as the forward tug can keep position, we can keep the ship under control.ship 4 

Under stern motion (fig. 23), with the pivot point aft, 200 feet from the stern, we  put a very heavy load on the forward tug. The rotational moment of the beam wind is then 8,640 feet/tons, which requires about a 20-ton pull of the forward tug to check, as the tug’s lever is about 450 feet.

Under lateral motion there will be an additional dynamic load on the tugs’ lines proportionate to the displacement of the ship and the ship’s lateral velocity.

A potential swing to starboard has to be anticipated by checking lateral motion all the time. Once a rotational motion is on, there is rotational momentum. With a ship of this size, the resulting load can vastly exceed the backing power of the for­ward tug and the breaking strength of its lines if the tug falls too heavily into them.

It can be seen that the tug is at an advan­tage when made fast as far forward as it can safely work.

In the situation described, there is little or no safety margin. We would not will­ingly take the ship in under this condi­tion, particularly not with a current from aft; however, with a 20-knot wind, on com­ing in, a sudden increase in wind speed from 20 to 25 knots may occur when the ship is already committed to the berth.



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From Marine Enclyopedia to MARINE GYAAN ACADEMY in Lucknow - Preparing YOUTH to become SEAFARERS ( for IMU-CET and various courses) From Marine Enclyopedia to MARINE GYAAN ACADEMY in Lucknow - Preparing YOUTH to become SEAFARERS ( for IMU-CET and various courses) From Marine Enclyopedia to MARINE GYAAN ACADEMY in Lucknow - Preparing YOUTH to become SEAFARERS ( for IMU-CET and various courses) From Marine Enclyopedia to MARINE GYAAN ACADEMY in Lucknow - Preparing YOUTH to become SEAFARERS ( for IMU-CET and various courses)