**In a vessel of 8800 tonnes displacement and KG 6.2m, 200 tonnes of cargo was loaded in the lower hold 1.7m above the keel. Find the final KG.**

**Solution:**

**Solution:**

**Given:-**

**Weight = 8800t,**

** Original KG =6.2m,**

** Cargo loaded = 200t,**

** KG = 1.7m**

Ship’s weight |
KG |
VM |

8800 t | 6.2m | 54560tm |

(+) 200 load | 1.7m | Final VM 54900 tm |

**Final W – 9000 t Final VM 54900 tm**

**So, we can calculate**

**Final KG = (Final VM/ Final W)**

** Final KG = (54900 / 9000)**

** = 6.1m**

**Here ‘VM’ stands for vertical moments.**

**600 tonnes of cargo were discharged from a vessel from the upper 11m above the keel. In the original KG displacement were 6m and 12600 tonnes, calculate the KG.**

**Solution:-**

**Solution:-**

**Given:-**

** Weight =12600 t**

** Original KG =6m**

** Cargo discharged = 600 t,**

**Cargo discharge 11 m above the keel**

Ship’s weight |
KG |
VM |

12,600t | 6m | 75,600tm |

( -) 600t ( discharge) | 11m | (-) 6600tm |

**Final Weight =12000 t Final VM =69000tm**

**We know that :**

**Final KG = (Final VM / Final Weight)**

**Final KG = ( 69,000 / 12000)**

**= 5.75m**

**In a vessel of 9900 tonnes displacement and KG 4m, a heavy lift of 100 tonnes is loaded on the UD (KG 15m ). Find the final KG.**

**Solution:**

**Solution:**

Ship’s weight |
KG |
VM |

12,600t | 4m | 39,600tm |

(+)100 t load | 15m | ( +)1500tm |

**Final W 10000t Final VM =41000tm**

**We know that:**

**Final KG = (Final VM / Final Weight)**

** Final KG = ( 41000 / 10000 )**

** = 4.11m.**

**500 tonnes of cargo of discharge from the lower the lower hold (KG 3m ) of a vessel whose displacement and KG before discharging were 11500 tonnes and 6.3m . Find the final KG.**

**Solution:**

**Solution:**

**Given:-**

**Weight = 11500t**

** Initial KG = 6.3m**

** Cargo discharged = 500t, KG =3m**

Ship’s weight |
KG |
VM |

11500t | 4m | 39,600tm |

(+)100 t load | 15m | ( +)1500tm |

**Final W =11000t Final VM =70950tm**

**We know that:**

**Final KG = (Final VM / Final Weight)**

** Final KG = (70,950/11000)**

** =6.45m**

**500 tonnes of cargo was shifted 15 meters vertically downwards in a vessel of 10000 tonnes displacement. Find the effect it has on the KG of the vessel and whether KG increases or decreases.**

**Solution:**

**Solution:**

**Given:-**

**Weight =10000t,**

** Cargo shifted downward =500t,**

**We know that:-**

**GG1() = (w x d)/( total weight)**

** = (500 x 15)/ 10000**

** =0.75m**

**Since, The weight is shifted vertically downward, the KG of ship will also go down parallel to the KG of the weight**

**Hence, KG of the ship decrease by 0.75m**

*In a vessel of 9000 tonnes displacement , KG 10.5m, 300 tonnes of cargo was shifted from the LH (KG 2.5m)to the UDC (KG 11.5m). Find the resultant KG of teh vessel.*

*Solution :*

*Solution :*

**Weight =9000 t**

** Original KG = 10.5m ,**

** Cargo shifted = 300 t**

**Vertical Distance of cargo shifted**

** = (height of UD – height of LH)**

** = (11.5 -2.5)**

** = 9m upwards.**

Ship’s weight |
KG |
VM |

9000t | 10.5m | 94500tm |

(+)300t | 9m | (+)2700tm |

**Final W = 9000 Final VM =200t**

**We know that :**

**Final KG = (Final VM / Final Weight)**

** Final KG = (97200 / 9,000)**

** = 10.8m.**

**In a vessel of 9009 tones displacement, KG 8.7m, how many tonnes of cargo can be loaded on the upper deck (KG 15m ) so that the final KG would be comes 9m.**

**Solution:-**

**Solution:-**

**Given:-**

** Weight = 9009 t,**

** Original KG =8.7m,**

**Let cargo loaded be X tonnes**

** Final KG =9m**

Ship’s weight |
KG |
VM |

9009 t | 8.7m | 94500tm |

(+) X t (load) | 15m | (+) (15 X) tm |

**Final W = (9009 + X) t Final VM =(78378.3 + 15X) tm**

**We know that:**

**Final KG = (Final VM / Final Weight)**

** Final KG = (78378.3 +15X ) /(9009 + X)**

** 9.0 = (78378.3 + 15X)/ (9009+X)**

** 9 x (9009+X) = (78378.3 + 15X)**

** (81081 + 9X) = (15X + 78378.3)**

** Hence, 6X = 78378 .3 – 81081**

** 6X = 2702.7t**

** X = 450.45 t**

*A heavy lift derrick , whose head is 20m above the keel , is to shift a locomotive weighing 300 tonnes from the UD (KG 8m ) to the LH (KG 2m). If the displacement and initial KG of the vessel were 12000 tonnes and 7.6m, find the KG of the vessels**When the derrick has taken the weight off the UD and**After shifting is over.*

*Solution:*

*Solution:*

**Given:**

** Weight = 12000t,**

** Initial KG =7.6m,**

** Cargo shifted = 300t,**

** Change of KG = (8 – 2)**

** = 6m downwards**

**Derrick Height = 20m,**

** KG of the Weight = 8m**

**(since the weight is on the UD)**

**Case – 1**

**Case – 1**

Ship’s weight |
KG |
VM |

12000 t | 7.6m | 91200tm |

300t (shift) | 12m | (+) 3600 tm |

**Final W =12000 t Final VM =94800tm**

**We know that:**

**Final KG = (Final VM / Final Weight)**

** FKG = (94800 / 12000)**

** = 7.9m**

**Case – 2**

**Case – 2**

Ship’s weight |
KG |
VM |

12000 t | 7.6m | 91200tm |

300t (shift) | 6m | (-)1800 tm |

**Final W =12000 Final VM = 89400tm**

**We know that:**

**Final KG = (Final VM / Final Weight)**

** Final KG = (89400 / 12000)**

** = 7.45m.**

**On a vessel of 4,950 tonnes displacement, KG 9.2m, the ship’s jumbo derrick is to be load a weight of 50 tonnes from the wharf , on to the UD( KG 8m) . if the head of the derrick is 25m above the keel , calculate the KG of the vessel****when the weight is hanging by the derrick on the centre line but 2m above the UD , and****after loading .**

**Solution:**

**Solution:**

**Given:-**

** Weight = 4950t,**

** Initial KG = 9.2m**

** Cargo loaded = 50t ,**

** UD KG =8m**

** Height of the derrick = 25m**

**Case – 1**

**Case – 1**

Ship’s weight |
KG |
VM |

4950 t | 9.2m | 45540 tm |

(+) 50t (load) | 25m | (+) 1250 tm |

**Final W = 5000t FVM = 46790tm**

**We know that:**

**Final KG = (Final VM / Final Weight)**

** Final KG = (46790 / 5000)**

** = 9.358m**

**Case – 2**

**Case – 2**

Ship’s weight |
KG |
VM |

4950 t | 9.2m | 45540 tm |

(+) 50t (load) | 8m | (+) 400 tm |

**Final W = 5000t Final VM = 45940tm**

**We know that:**

**Final KG = (Final VM / Final Weight)**

** Final KG = (45940 / 5000)**

** = 9.188m**

**A ship’s derrick, whose head is 22m above the keel, is used to be discharge a weight of 20 tonnes (KG 5m), lying on the centre line. If the vessel’s displacement and KG before discharging were 6000 tonnes and 8m. Calculate the KG****As soon as the derrick lifts the weight and****After discharging .**

**Solution:-**

**Solution:-**

**Given:-**

** Weight = 6000t,**

** Original KG = 8m,**

** Cargo discharged = 20t,**

** KG of cargo discharged = 5m**

** Height of the derrick = 22m**

**Case – 1**

**Case – 1**

Ship’s weight |
KG |
VM |

6000t | 8m | 48 000 tm |

20t | 17m | (+) 340 tm |

*Final W = 6000 Final VM 48340 tm*

*We know that:*

*Final KG = (Final VM / Final Weight)*

* Final KG = (48340 / 6,000)*

* = 8.056m*

**Case – 2**

**Case – 2**

Ship’s weight |
KG |
VM |

6000t | 8m | 48 000 tm |

(-)20t (discharge) | 5m | (-) 100 tm |

**Final W =5980t Final VM = 47900 tm**

**We know that:**

**Final KG = (Final VM / Final Weight)**

** Final KG = (47900/5980)**

** = 8.010m.**